Exercise: Linear Functions and Their Properties

by Electra Radioti
Linear Functions and Analytical Geometry

Problem Statement:

Given the function f(x)=3x+9f(x) = 3x + 9:

  1. (a) Describe the shape of the graph of the function and find algebraically the points where it intersects the X and Y axes.
  2. (b) Find algebraically the point of intersection of the graphs of f(x)f(x) and g(x)=−x+11g(x) = -x + 11.
  3. (c) If a line passes through the point (2,1)(2, 1) and has a slope of −2-2, determine its equation.
  4. (d) Prove that the line passing through the points (−2,−8)(-2, -8) and (2,4)(2, 4) is parallel to the graph of the function ϕ(x)=3x+1\phi(x) = 3x + 1.

Blog Post: Understanding Linear Functions with Worked Examples

Linear functions are fundamental in mathematics, representing relationships with a constant rate of change. In this blog post, we will explore and solve a set of problems to understand their properties and applications.


(a) Shape and Intercepts of f(x)=3x+9f(x) = 3x + 9

The function f(x)=3x+9f(x) = 3x + 9 is a linear equation, representing a straight line. The slope (mm) of the line is 33, and the y-intercept (bb) is 99.

To find the intercepts:

  • X-axis: Set f(x)=0f(x) = 0

    3x+9=0  ⟹  x=−33x + 9 = 0 \implies x = -3Thus, the X-intercept is (−3,0)(-3, 0).

  • Y-axis: Set x=0x = 0

    f(0)=3(0)+9=9f(0) = 3(0) + 9 = 9Thus, the Y-intercept is (0,9)(0, 9).

Graphically, the line crosses the X-axis at (−3,0)(-3, 0) and the Y-axis at (0,9)(0, 9).


(b) Intersection of f(x)=3x+9f(x) = 3x + 9 and g(x)=−x+11g(x) = -x + 11

To find the intersection point, set f(x)=g(x)f(x) = g(x):

3x+9=−x+113x + 9 = -x + 11 4x=2  ⟹  x=124x = 2 \implies x = \frac{1}{2}

Substitute x=12x = \frac{1}{2} into either equation, e.g., f(x)f(x):

f(12)=3(12)+9=32+9=212f\left(\frac{1}{2}\right) = 3\left(\frac{1}{2}\right) + 9 = \frac{3}{2} + 9 = \frac{21}{2}

Thus, the intersection point is (12,212)\left(\frac{1}{2}, \frac{21}{2}\right).


(c) Equation of a Line through (2,1)(2, 1) with Slope −2-2

The slope-intercept form of a line is y=mx+cy = mx + c, where mm is the slope and cc is the y-intercept.

Using the point (2,1)(2, 1):

1=−2(2)+c  ⟹  1=−4+c  ⟹  c=51 = -2(2) + c \implies 1 = -4 + c \implies c = 5

Thus, the equation is:

y=−2x+5y = -2x + 5


(d) Proving Parallelism of Two Lines

Two lines are parallel if they have the same slope.

  • The slope of the line passing through (−2,−8)(-2, -8) and (2,4)(2, 4):

    m=4−(−8)2−(−2)=4+82+2=124=3m = \frac{4 – (-8)}{2 – (-2)} = \frac{4 + 8}{2 + 2} = \frac{12}{4} = 3

  • The slope of Ï•(x)=3x+1\phi(x) = 3x + 1 is 33.

Since both lines have the same slope (33), they are parallel.


Conclusion

These exercises highlight the key properties of linear functions, such as intercepts, slopes, and conditions for parallelism. By solving such problems, students gain a deeper understanding of how linear equations model relationships and interact graphically. Keep practicing, and you’ll master these concepts in no time!

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