Techniques of Integration in Economics: Substitution, Integration by Parts, and Partial Fractions

by Electra Radioti
Techniques of Integration

Introduction
In economic analysis, integration allows us to go from marginal to total quantities, determine areas under curves, and model consumer and producer surplus. But many economic functions are not easy to integrate directly. That’s why we use specialized techniques to simplify integrals and make them solvable.

This post introduces three key techniques of integration used in economics and applied mathematics:

  1. Substitution
  2. Integration by Parts
  3. Partial Fractions

1. Substitution Method (Change of Variables)
This technique simplifies a complicated function by substituting a part of it with a single variable, often denoted uu.

Formula:

If u=g(x)u = g(x), then:
f(g(x))g(x)dx=f(u)du\int f(g(x))g'(x) dx = \int f(u) du

Example:

Let MC(q)=6(2q+1)4MC(q) = 6(2q + 1)^4. Then:
MC(q)dq=6(2q+1)4dq\int MC(q) dq = \int 6(2q + 1)^4 dq
Let u=2q+1u = 2q + 1, so du=2dqdu = 2 dq, thus dq=du2dq = \frac{du}{2}

6(2q+1)4dq=6u412du=3u4du=3u55+C=35(2q+1)5+C\int 6(2q + 1)^4 dq = 6 \int u^4 \cdot \frac{1}{2} du = 3 \int u^4 du = 3 \cdot \frac{u^5}{5} + C = \frac{3}{5}(2q + 1)^5 + C

Economic Relevance: Used when marginal cost/revenue involves power expressions or nested linear terms.


2. Integration by Parts
This technique comes from the product rule in differentiation and is useful when integrating the product of two different types of functions.

Formula:

udv=uvvdu\int u \cdot dv = uv – \int v \cdot du

Where:

  • uu is chosen to simplify when differentiated
  • dvdv is easily integrable

Example:

xexdx\int x e^x dx
Let u=xdu=dxu = x \Rightarrow du = dx
Let dv=exdxv=exdv = e^x dx \Rightarrow v = e^x

xexdx=xexexdx=xexex+C=ex(x1)+C\int x e^x dx = x e^x – \int e^x dx = x e^x – e^x + C = e^x(x – 1) + C

Economic Relevance: Appears in utility models, discounted cash flow analysis, and exponential growth functions.


3. Integration Using Partial Fractions
Used when dealing with rational functions P(x)Q(x)\frac{P(x)}{Q(x)}, especially when the degree of the numerator is less than the degree of the denominator.

Example:

1x21dx\int \frac{1}{x^2 – 1} dx
Factor denominator: x21=(x1)(x+1)x^2 – 1 = (x – 1)(x + 1)

Decompose:
1x21=Ax1+Bx+1\frac{1}{x^2 – 1} = \frac{A}{x – 1} + \frac{B}{x + 1}
Solve for A and B (algebraically), then integrate:
(12(x1)12(x+1))dx=12lnx112lnx+1+C\int \left( \frac{1}{2(x – 1)} – \frac{1}{2(x + 1)} \right) dx = \frac{1}{2} \ln|x – 1| – \frac{1}{2} \ln|x + 1| + C

Economic Relevance: Often used in microeconomic models involving elasticity, equilibrium, or rational price functions.


Tips for Choosing a Method

Problem Type Recommended Technique
Composite function (e.g., f(g(x))f(g(x))) Substitution
Product of polynomial & exponential/log Integration by parts
Rational function (P(x)Q(x)\frac{P(x)}{Q(x)}) Partial fractions (after simplification)

Conclusion
Mastering these integration techniques expands your ability to solve real-world economic problems involving cost, revenue, utility, and more. Whether you’re working with demand curves, marginal analysis, or complex revenue functions, substitution, integration by parts, and partial fractions turn difficult integrals into solvable ones.

With consistent practice, these methods become invaluable tools in your mathematical economics toolkit.


Further Reading

  • Chiang & Wainwright, Fundamental Methods of Mathematical Economics
  • Stewart, J. Calculus for the Life and Social Sciences

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